20=4c+32

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Solution for 20=4c+32 equation: 



20=4c+32

We move all terms to the left:

20-(4c+32)=0

We get rid of parentheses

-4c-32+20=0

We add all the numbers together, and all the variables

-4c-12=0

We move all terms containing c to the left, all other terms to the right

-4c=12

c=12/-4

c=-3

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