20=5(2x+4)+10(4x+1)

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Solution for 20=5(2x+4)+10(4x+1) equation:



20=5(2x+4)+10(4x+1)
We move all terms to the left:
20-(5(2x+4)+10(4x+1))=0
We calculate terms in parentheses: -(5(2x+4)+10(4x+1)), so:
5(2x+4)+10(4x+1)
We multiply parentheses
10x+40x+20+10
We add all the numbers together, and all the variables
50x+30
Back to the equation:
-(50x+30)
We get rid of parentheses
-50x-30+20=0
We add all the numbers together, and all the variables
-50x-10=0
We move all terms containing x to the left, all other terms to the right
-50x=10
x=10/-50
x=-1/5

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