20=5(2x+4)+10(4x+1)

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Solution for 20=5(2x+4)+10(4x+1) equation: 



20=5(2x+4)+10(4x+1)

We move all terms to the left:

20-(5(2x+4)+10(4x+1))=0



We calculate terms in parentheses: -(5(2x+4)+10(4x+1)), so:

5(2x+4)+10(4x+1)

We multiply parentheses

10x+40x+20+10

We add all the numbers together, and all the variables

50x+30

Back to the equation:

-(50x+30)



We get rid of parentheses

-50x-30+20=0

We add all the numbers together, and all the variables

-50x-10=0

We move all terms containing x to the left, all other terms to the right

-50x=10

x=10/-50

x=-1/5

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