20=5(c+2)+2

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Solution for 20=5(c+2)+2 equation: 



20=5(c+2)+2

We move all terms to the left:

20-(5(c+2)+2)=0



We calculate terms in parentheses: -(5(c+2)+2), so:

5(c+2)+2

We multiply parentheses

5c+10+2

We add all the numbers together, and all the variables

5c+12

Back to the equation:

-(5c+12)



We get rid of parentheses

-5c-12+20=0

We add all the numbers together, and all the variables

-5c+8=0

We move all terms containing c to the left, all other terms to the right

-5c=-8

c=-8/-5

c=1+3/5

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