20=5(r-3)

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Solution for 20=5(r-3) equation: 



20=5(r-3)

We move all terms to the left:

20-(5(r-3))=0



We calculate terms in parentheses: -(5(r-3)), so:

5(r-3)

We multiply parentheses

5r-15

Back to the equation:

-(5r-15)



We get rid of parentheses

-5r+15+20=0

We add all the numbers together, and all the variables

-5r+35=0

We move all terms containing r to the left, all other terms to the right

-5r=-35

r=-35/-5

r=+7

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