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20=5(x+1)-(2+x)-3x
We move all terms to the left:
20-(5(x+1)-(2+x)-3x)=0
We add all the numbers together, and all the variables
-(5(x+1)-(x+2)-3x)+20=0
We calculate terms in parentheses: -(5(x+1)-(x+2)-3x), so:We get rid of parentheses
5(x+1)-(x+2)-3x
We add all the numbers together, and all the variables
-3x+5(x+1)-(x+2)
We multiply parentheses
-3x+5x-(x+2)+5
We get rid of parentheses
-3x+5x-x-2+5
We add all the numbers together, and all the variables
x+3
Back to the equation:
-(x+3)
-x-3+20=0
We add all the numbers together, and all the variables
-1x+17=0
We move all terms containing x to the left, all other terms to the right
-x=-17
x=-17/-1
x=+17
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