20=5+3(t+5)

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Solution for 20=5+3(t+5) equation:



20=5+3(t+5)
We move all terms to the left:
20-(5+3(t+5))=0
We calculate terms in parentheses: -(5+3(t+5)), so:
5+3(t+5)
determiningTheFunctionDomain 3(t+5)+5
We multiply parentheses
3t+15+5
We add all the numbers together, and all the variables
3t+20
Back to the equation:
-(3t+20)
We get rid of parentheses
-3t-20+20=0
We add all the numbers together, and all the variables
-3t=0
t=0/-3
t=0

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