20=5+3(t-2)

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Solution for 20=5+3(t-2) equation: 



20=5+3(t-2)

We move all terms to the left:

20-(5+3(t-2))=0



We calculate terms in parentheses: -(5+3(t-2)), so:

5+3(t-2)

determiningTheFunctionDomain
3(t-2)+5

We multiply parentheses

3t-6+5

We add all the numbers together, and all the variables

3t-1

Back to the equation:

-(3t-1)



We get rid of parentheses

-3t+1+20=0

We add all the numbers together, and all the variables

-3t+21=0

We move all terms containing t to the left, all other terms to the right

-3t=-21

t=-21/-3

t=+7

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