20=5+3(t-2)

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Solution for 20=5+3(t-2) equation:



20=5+3(t-2)
We move all terms to the left:
20-(5+3(t-2))=0
We calculate terms in parentheses: -(5+3(t-2)), so:
5+3(t-2)
determiningTheFunctionDomain 3(t-2)+5
We multiply parentheses
3t-6+5
We add all the numbers together, and all the variables
3t-1
Back to the equation:
-(3t-1)
We get rid of parentheses
-3t+1+20=0
We add all the numbers together, and all the variables
-3t+21=0
We move all terms containing t to the left, all other terms to the right
-3t=-21
t=-21/-3
t=+7

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