20=5-(3+y)

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Solution for 20=5-(3+y) equation: 



20=5-(3+y)

We move all terms to the left:

20-(5-(3+y))=0

We add all the numbers together, and all the variables

-(5-(y+3))+20=0



We calculate terms in parentheses: -(5-(y+3)), so:

5-(y+3)

determiningTheFunctionDomain
-(y+3)+5

We get rid of parentheses

-y-3+5

We add all the numbers together, and all the variables

-1y+2

Back to the equation:

-(-1y+2)



We get rid of parentheses

1y-2+20=0

We add all the numbers together, and all the variables

y+18=0

We move all terms containing y to the left, all other terms to the right

y=-18

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