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20=5/2(2x-4)
We move all terms to the left:
20-(5/2(2x-4))=0
Domain of the equation: 2(2x-4))!=0We multiply all the terms by the denominator
x∈R
-(5+20*2(2x-4))=0
We calculate terms in parentheses: -(5+20*2(2x-4)), so:We add all the numbers together, and all the variables
5+20*2(2x-4)
determiningTheFunctionDomain 20*2(2x-4)+5
Wy multiply elements
40x(2+5
Back to the equation:
-(40x(2+5)
-(40x7=0
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