20=5x(2-x)

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Solution for 20=5x(2-x) equation: 



20=5x(2-x)

We move all terms to the left:

20-(5x(2-x))=0

We add all the numbers together, and all the variables

-(5x(-1x+2))+20=0



We calculate terms in parentheses: -(5x(-1x+2)), so:

5x(-1x+2)

We multiply parentheses

-5x^2+10x

Back to the equation:

-(-5x^2+10x)



We get rid of parentheses

5x^2-10x+20=0

a = 5; b = -10; c = +20;
Δ = b2-4ac
Δ = -102-4·5·20
Δ = -300
Delta is less than zero, so there is no solution for the equation

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