20=6(2-x)+8

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Solution for 20=6(2-x)+8 equation: 



20=6(2-x)+8

We move all terms to the left:

20-(6(2-x)+8)=0

We add all the numbers together, and all the variables

-(6(-1x+2)+8)+20=0



We calculate terms in parentheses: -(6(-1x+2)+8), so:

6(-1x+2)+8

We multiply parentheses

-6x+12+8

We add all the numbers together, and all the variables

-6x+20

Back to the equation:

-(-6x+20)



We get rid of parentheses

6x-20+20=0

We add all the numbers together, and all the variables

6x=0

x=0/6

x=0

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