20=6(4x+1)+2(-5+3x)

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Solution for 20=6(4x+1)+2(-5+3x) equation: 



20=6(4x+1)+2(-5+3x)

We move all terms to the left:

20-(6(4x+1)+2(-5+3x))=0

We add all the numbers together, and all the variables

-(6(4x+1)+2(3x-5))+20=0



We calculate terms in parentheses: -(6(4x+1)+2(3x-5)), so:

6(4x+1)+2(3x-5)

We multiply parentheses

24x+6x+6-10

We add all the numbers together, and all the variables

30x-4

Back to the equation:

-(30x-4)



We get rid of parentheses

-30x+4+20=0

We add all the numbers together, and all the variables

-30x+24=0

We move all terms containing x to the left, all other terms to the right

-30x=-24

x=-24/-30

x=4/5

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