20=6(x+2)-2x

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Solution for 20=6(x+2)-2x equation: 



20=6(x+2)-2x

We move all terms to the left:

20-(6(x+2)-2x)=0



We calculate terms in parentheses: -(6(x+2)-2x), so:

6(x+2)-2x

We add all the numbers together, and all the variables

-2x+6(x+2)

We multiply parentheses

-2x+6x+12

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

-4x-12+20=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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