20=6z-52

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Solution for 20=6z-52 equation: 



20=6z-52

We move all terms to the left:

20-(6z-52)=0

We get rid of parentheses

-6z+52+20=0

We add all the numbers together, and all the variables

-6z+72=0

We move all terms containing z to the left, all other terms to the right

-6z=-72

z=-72/-6

z=+12

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