20=7/2(2)+x(2)

Solution for 20=7/2(2)+x(2) equation:

20=7/2(2)+x(2)

We move all terms to the left:

20-(7/2(2)+x(2))=0


Domain of the equation: 22+x2)!=0

We move all terms containing x to the left, all other terms to the right

x2)!=-22

x!=-22/1

x!=-22

x∈R


We add all the numbers together, and all the variables

-(+x^2+7/22)+20=0

We get rid of parentheses

-x^2+20-7/22=0

We multiply all the terms by the denominator


-x^2*22-7+20*22=0

We add all the numbers together, and all the variables

-x^2*22+433=0

Wy multiply elements

-22x^2+433=0

a = -22; b = 0; c = +433;
Δ = b2-4ac
Δ = 02-4·(-22)·433
Δ = 38104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{38104}=\sqrt{4*9526}=\sqrt{4}*\sqrt{9526}=2\sqrt{9526}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{9526}}{2*-22}=\frac{0-2\sqrt{9526}}{-44}
=-\frac{2\sqrt{9526}}{-44}
=-\frac{\sqrt{9526}}{-22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{9526}}{2*-22}=\frac{0+2\sqrt{9526}}{-44}
=\frac{2\sqrt{9526}}{-44}
=\frac{\sqrt{9526}}{-22}
$