20=78-(2x-4x2)

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Solution for 20=78-(2x-4x2) equation: 



20=78-(2x-4x^2)

We move all terms to the left:

20-(78-(2x-4x^2))=0



We calculate terms in parentheses: -(78-(2x-4x^2)), so:

78-(2x-4x^2)

determiningTheFunctionDomain
-(2x-4x^2)+78

We get rid of parentheses

4x^2-2x+78

Back to the equation:

-(4x^2-2x+78)



We get rid of parentheses

-4x^2+2x-78+20=0

We add all the numbers together, and all the variables

-4x^2+2x-58=0

a = -4; b = 2; c = -58;
Δ = b2-4ac
Δ = 22-4·(-4)·(-58)
Δ = -924
Delta is less than zero, so there is no solution for the equation

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