20=8y+2(y-5)

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Solution for 20=8y+2(y-5) equation: 



20=8y+2(y-5)

We move all terms to the left:

20-(8y+2(y-5))=0



We calculate terms in parentheses: -(8y+2(y-5)), so:

8y+2(y-5)

We multiply parentheses

8y+2y-10

We add all the numbers together, and all the variables

10y-10

Back to the equation:

-(10y-10)



We get rid of parentheses

-10y+10+20=0

We add all the numbers together, and all the variables

-10y+30=0

We move all terms containing y to the left, all other terms to the right

-10y=-30

y=-30/-10

y=+3

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