20=9(1-d)+2

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Solution for 20=9(1-d)+2 equation: 



20=9(1-d)+2

We move all terms to the left:

20-(9(1-d)+2)=0

We add all the numbers together, and all the variables

-(9(-1d+1)+2)+20=0



We calculate terms in parentheses: -(9(-1d+1)+2), so:

9(-1d+1)+2

We multiply parentheses

-9d+9+2

We add all the numbers together, and all the variables

-9d+11

Back to the equation:

-(-9d+11)



We get rid of parentheses

9d-11+20=0

We add all the numbers together, and all the variables

9d+9=0

We move all terms containing d to the left, all other terms to the right

9d=-9

d=-9/9

d=-1

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