20=x/(0.3-x)(0.4-x)

Solution for 20=x/(0.3-x)(0.4-x) equation:

20=x/(0.3-x)(0.4-x)

We move all terms to the left:

20-(x/(0.3-x)(0.4-x))=0


Domain of the equation: (0.3-x)(0.4-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.4-x)!=-0.3

x∈R


We add all the numbers together, and all the variables

-(x/(-1x+0.3)(-1x+0.4))+20=0

We multiply parentheses ..

-(x/(+x^2-0.4x-0.3x+0.12))+20=0

We multiply all the terms by the denominator


-(x+20*(+x^2-0.4x-0.3x+0.12))=0


We calculate terms in parentheses: -(x+20*(+x^2-0.4x-0.3x+0.12)), so:

x+20*(+x^2-0.4x-0.3x+0.12)

determiningTheFunctionDomain
20*(+x^2-0.4x-0.3x+0.12)+x

We multiply parentheses

20x^2+0x+0x+x+2.4

We add all the numbers together, and all the variables

20x^2+3x+2.4

Back to the equation:

-(20x^2+3x+2.4)


We get rid of parentheses

-20x^2-3x-2.4=0

a = -20; b = -3; c = -2.4;
Δ = b2-4ac
Δ = -32-4·(-20)·(-2.4)
Δ = -183
Delta is less than zero, so there is no solution for the equation