20b-4b=7(b+2b)+5

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Solution for 20b-4b=7(b+2b)+5 equation: 



20b-4b=7(b+2b)+5

We move all terms to the left:

20b-4b-(7(b+2b)+5)=0

We add all the numbers together, and all the variables

20b-4b-(7(+3b)+5)=0

We add all the numbers together, and all the variables

16b-(7(+3b)+5)=0



We calculate terms in parentheses: -(7(+3b)+5), so:

7(+3b)+5

We multiply parentheses

21b+5

Back to the equation:

-(21b+5)



We get rid of parentheses

16b-21b-5=0

We add all the numbers together, and all the variables

-5b-5=0

We move all terms containing b to the left, all other terms to the right

-5b=5

b=5/-5

b=-1

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