20c+(6c+3)+(11c-8)=180

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Solution for 20c+(6c+3)+(11c-8)=180 equation: 



20c+(6c+3)+(11c-8)=180

We move all terms to the left:

20c+(6c+3)+(11c-8)-(180)=0

We get rid of parentheses

20c+6c+11c+3-8-180=0

We add all the numbers together, and all the variables

37c-185=0

We move all terms containing c to the left, all other terms to the right

37c=185

c=185/37

c=5

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