20f+(-8f-15)=(4f-5)

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Solution for 20f+(-8f-15)=(4f-5) equation: 



20f+(-8f-15)=(4f-5)

We move all terms to the left:

20f+(-8f-15)-((4f-5))=0

We get rid of parentheses

20f-8f-((4f-5))-15=0



We calculate terms in parentheses: -((4f-5)), so:

(4f-5)

We get rid of parentheses

4f-5

Back to the equation:

-(4f-5)



We add all the numbers together, and all the variables

12f-(4f-5)-15=0

We get rid of parentheses

12f-4f+5-15=0

We add all the numbers together, and all the variables

8f-10=0

We move all terms containing f to the left, all other terms to the right

8f=10

f=10/8

f=1+1/4

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