20f+(-8f-15)=3(4f+-5)

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Solution for 20f+(-8f-15)=3(4f+-5) equation: 



20f+(-8f-15)=3(4f+-5)

We move all terms to the left:

20f+(-8f-15)-(3(4f+-5))=0

We add all the numbers together, and all the variables

20f+(-8f-15)-(3(4f-5))=0

We get rid of parentheses

20f-8f-(3(4f-5))-15=0



We calculate terms in parentheses: -(3(4f-5)), so:

3(4f-5)

We multiply parentheses

12f-15

Back to the equation:

-(12f-15)



We add all the numbers together, and all the variables

12f-(12f-15)-15=0

We get rid of parentheses

12f-12f+15-15=0

We add all the numbers together, and all the variables

=0

f=0/1

f=0

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