20f+(-8f-15)=3(4f-5)

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Solution for 20f+(-8f-15)=3(4f-5) equation:


Simplifying
20f + (-8f + -15) = 3(4f + -5)

Reorder the terms:
20f + (-15 + -8f) = 3(4f + -5)

Remove parenthesis around (-15 + -8f)
20f + -15 + -8f = 3(4f + -5)

Reorder the terms:
-15 + 20f + -8f = 3(4f + -5)

Combine like terms: 20f + -8f = 12f
-15 + 12f = 3(4f + -5)

Reorder the terms:
-15 + 12f = 3(-5 + 4f)
-15 + 12f = (-5 * 3 + 4f * 3)
-15 + 12f = (-15 + 12f)

Add '15' to each side of the equation.
-15 + 15 + 12f = -15 + 15 + 12f

Combine like terms: -15 + 15 = 0
0 + 12f = -15 + 15 + 12f
12f = -15 + 15 + 12f

Combine like terms: -15 + 15 = 0
12f = 0 + 12f
12f = 12f

Add '-12f' to each side of the equation.
12f + -12f = 12f + -12f

Combine like terms: 12f + -12f = 0
0 = 12f + -12f

Combine like terms: 12f + -12f = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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