20g2-16g+0=0

Solution for 20g2-16g+0=0 equation:

20g^2-16g+0=0

We add all the numbers together, and all the variables

20g^2-16g=0

a = 20; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·20·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*20}=\frac{0}{40}
=0
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*20}=\frac{32}{40}
=4/5
$