20g2=16g

Solution for 20g2=16g equation:

20g^2=16g

We move all terms to the left:

20g^2-(16g)=0

a = 20; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·20·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*20}=\frac{0}{40}
=0
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*20}=\frac{32}{40}
=4/5
$