20h2=480

Solution for 20h2=480 equation:

20h^2=480

We move all terms to the left:

20h^2-(480)=0

a = 20; b = 0; c = -480;
Δ = b2-4ac
Δ = 02-4·20·(-480)
Δ = 38400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{38400}=\sqrt{6400*6}=\sqrt{6400}*\sqrt{6}=80\sqrt{6}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{6}}{2*20}=\frac{0-80\sqrt{6}}{40}
=-\frac{80\sqrt{6}}{40}
=-2\sqrt{6}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{6}}{2*20}=\frac{0+80\sqrt{6}}{40}
=\frac{80\sqrt{6}}{40}
=2\sqrt{6}
$