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20t(t-5)=5t
We move all terms to the left:
20t(t-5)-(5t)=0
We add all the numbers together, and all the variables
-5t+20t(t-5)=0
We multiply parentheses
20t^2-5t-100t=0
We add all the numbers together, and all the variables
20t^2-105t=0
a = 20; b = -105; c = 0;
Δ = b2-4ac
Δ = -1052-4·20·0
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11025}=105$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-105}{2*20}=\frac{0}{40} =0 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+105}{2*20}=\frac{210}{40} =5+1/4 $
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