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20w^2+88w+32=0
a = 20; b = 88; c = +32;
Δ = b2-4ac
Δ = 882-4·20·32
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-72}{2*20}=\frac{-160}{40} =-4 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+72}{2*20}=\frac{-16}{40} =-2/5 $
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