20x(2)=9x+18

Solution for 20x(2)=9x+18 equation:

20x(2)=9x+18

We move all terms to the left:

20x(2)-(9x+18)=0

We add all the numbers together, and all the variables

20x^2-(9x+18)=0

We get rid of parentheses

20x^2-9x-18=0

a = 20; b = -9; c = -18;
Δ = b2-4ac
Δ = -92-4·20·(-18)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-39}{2*20}=\frac{-30}{40}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+39}{2*20}=\frac{48}{40}
=1+1/5
$