20x+15-(6x-13)=9x+37-(5x+5)

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Solution for 20x+15-(6x-13)=9x+37-(5x+5) equation: 



20x+15-(6x-13)=9x+37-(5x+5)

We move all terms to the left:

20x+15-(6x-13)-(9x+37-(5x+5))=0

We get rid of parentheses

20x-6x-(9x+37-(5x+5))+13+15=0



We calculate terms in parentheses: -(9x+37-(5x+5)), so:

9x+37-(5x+5)

determiningTheFunctionDomain
9x-(5x+5)+37

We get rid of parentheses

9x-5x-5+37

We add all the numbers together, and all the variables

4x+32

Back to the equation:

-(4x+32)



We add all the numbers together, and all the variables

14x-(4x+32)+28=0

We get rid of parentheses

14x-4x-32+28=0

We add all the numbers together, and all the variables

10x-4=0

We move all terms containing x to the left, all other terms to the right

10x=4

x=4/10

x=2/5

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