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20x+15-(6x-13)=9x+37-(5x+5)
We move all terms to the left:
20x+15-(6x-13)-(9x+37-(5x+5))=0
We get rid of parentheses
20x-6x-(9x+37-(5x+5))+13+15=0
We calculate terms in parentheses: -(9x+37-(5x+5)), so:We add all the numbers together, and all the variables
9x+37-(5x+5)
determiningTheFunctionDomain 9x-(5x+5)+37
We get rid of parentheses
9x-5x-5+37
We add all the numbers together, and all the variables
4x+32
Back to the equation:
-(4x+32)
14x-(4x+32)+28=0
We get rid of parentheses
14x-4x-32+28=0
We add all the numbers together, and all the variables
10x-4=0
We move all terms containing x to the left, all other terms to the right
10x=4
x=4/10
x=2/5
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