20x+4(7x+5)=3(x-10)-40.

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Solution for 20x+4(7x+5)=3(x-10)-40. equation: 



20x+4(7x+5)=3(x-10)-40.

We move all terms to the left:

20x+4(7x+5)-(3(x-10)-40.)=0

We multiply parentheses

20x+28x-(3(x-10)-40.)+20=0



We calculate terms in parentheses: -(3(x-10)-40.), so:

3(x-10)-40.

We add all the numbers together, and all the variables

3(x-10)-40

We multiply parentheses

3x-30-40

We add all the numbers together, and all the variables

3x-70

Back to the equation:

-(3x-70)



We add all the numbers together, and all the variables

48x-(3x-70)+20=0

We get rid of parentheses

48x-3x+70+20=0

We add all the numbers together, and all the variables

45x+90=0

We move all terms containing x to the left, all other terms to the right

45x=-90

x=-90/45

x=-2

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