20x+4=3(20x-2)

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Solution for 20x+4=3(20x-2) equation: 



20x+4=3(20x-2)

We move all terms to the left:

20x+4-(3(20x-2))=0



We calculate terms in parentheses: -(3(20x-2)), so:

3(20x-2)

We multiply parentheses

60x-6

Back to the equation:

-(60x-6)



We get rid of parentheses

20x-60x+6+4=0

We add all the numbers together, and all the variables

-40x+10=0

We move all terms containing x to the left, all other terms to the right

-40x=-10

x=-10/-40

x=1/4

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