20x+58=21(x-2)

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Solution for 20x+58=21(x-2) equation: 



20x+58=21(x-2)

We move all terms to the left:

20x+58-(21(x-2))=0



We calculate terms in parentheses: -(21(x-2)), so:

21(x-2)

We multiply parentheses

21x-42

Back to the equation:

-(21x-42)



We get rid of parentheses

20x-21x+42+58=0

We add all the numbers together, and all the variables

-1x+100=0

We move all terms containing x to the left, all other terms to the right

-x=-100

x=-100/-1

x=+100

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