20x+5=(9x-2)+40

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Solution for 20x+5=(9x-2)+40 equation: 



20x+5=(9x-2)+40

We move all terms to the left:

20x+5-((9x-2)+40)=0



We calculate terms in parentheses: -((9x-2)+40), so:

(9x-2)+40

We get rid of parentheses

9x-2+40

We add all the numbers together, and all the variables

9x+38

Back to the equation:

-(9x+38)



We get rid of parentheses

20x-9x-38+5=0

We add all the numbers together, and all the variables

11x-33=0

We move all terms containing x to the left, all other terms to the right

11x=33

x=33/11

x=3

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