20x+60=5x2

Solution for 20x+60=5x2 equation:

20x+60=5x^2

We move all terms to the left:

20x+60-(5x^2)=0

determiningTheFunctionDomain
-5x^2+20x+60=0

a = -5; b = 20; c = +60;
Δ = b2-4ac
Δ = 202-4·(-5)·60
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-40}{2*-5}=\frac{-60}{-10}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+40}{2*-5}=\frac{20}{-10}
=-2
$