20x+8(1-x)=12

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Solution for 20x+8(1-x)=12 equation: 



20x+8(1-x)=12

We move all terms to the left:

20x+8(1-x)-(12)=0

We add all the numbers together, and all the variables

20x+8(-1x+1)-12=0

We multiply parentheses

20x-8x+8-12=0

We add all the numbers together, and all the variables

12x-4=0

We move all terms containing x to the left, all other terms to the right

12x=4

x=4/12

x=1/3

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