20x+8(2x+5)=12(x+3)+28

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Solution for 20x+8(2x+5)=12(x+3)+28 equation: 


Simplifying
20x + 8(2x + 5) = 12(x + 3) + 28

Reorder the terms:
20x + 8(5 + 2x) = 12(x + 3) + 28
20x + (5 * 8 + 2x * 8) = 12(x + 3) + 28
20x + (40 + 16x) = 12(x + 3) + 28

Reorder the terms:
40 + 20x + 16x = 12(x + 3) + 28

Combine like terms: 20x + 16x = 36x
40 + 36x = 12(x + 3) + 28

Reorder the terms:
40 + 36x = 12(3 + x) + 28
40 + 36x = (3 * 12 + x * 12) + 28
40 + 36x = (36 + 12x) + 28

Reorder the terms:
40 + 36x = 36 + 28 + 12x

Combine like terms: 36 + 28 = 64
40 + 36x = 64 + 12x

Solving
40 + 36x = 64 + 12x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12x' to each side of the equation.
40 + 36x + -12x = 64 + 12x + -12x

Combine like terms: 36x + -12x = 24x
40 + 24x = 64 + 12x + -12x

Combine like terms: 12x + -12x = 0
40 + 24x = 64 + 0
40 + 24x = 64

Add '-40' to each side of the equation.
40 + -40 + 24x = 64 + -40

Combine like terms: 40 + -40 = 0
0 + 24x = 64 + -40
24x = 64 + -40

Combine like terms: 64 + -40 = 24
24x = 24

Divide each side by '24'.
x = 1

Simplifying
x = 1

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