20x+x2=525

Solution for 20x+x2=525 equation:

20x+x2=525

We move all terms to the left:

20x+x2-(525)=0

We add all the numbers together, and all the variables

x^2+20x-525=0

a = 1; b = 20; c = -525;
Δ = b2-4ac
Δ = 202-4·1·(-525)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-50}{2*1}=\frac{-70}{2}
=-35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+50}{2*1}=\frac{30}{2}
=15
$