20x-16=4x2

Solution for 20x-16=4x2 equation:

20x-16=4x^2

We move all terms to the left:

20x-16-(4x^2)=0

determiningTheFunctionDomain
-4x^2+20x-16=0

a = -4; b = 20; c = -16;
Δ = b2-4ac
Δ = 202-4·(-4)·(-16)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-12}{2*-4}=\frac{-32}{-8}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+12}{2*-4}=\frac{-8}{-8}
=1
$