20x-19=5(3x-3)+5x-4

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Solution for 20x-19=5(3x-3)+5x-4 equation: 



20x-19=5(3x-3)+5x-4

We move all terms to the left:

20x-19-(5(3x-3)+5x-4)=0



We calculate terms in parentheses: -(5(3x-3)+5x-4), so:

5(3x-3)+5x-4

We add all the numbers together, and all the variables

5x+5(3x-3)-4

We multiply parentheses

5x+15x-15-4

We add all the numbers together, and all the variables

20x-19

Back to the equation:

-(20x-19)



We get rid of parentheses

20x-20x+19-19=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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