20x-2(4x-5)=4+6(2x+1)

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Solution for 20x-2(4x-5)=4+6(2x+1) equation: 



20x-2(4x-5)=4+6(2x+1)

We move all terms to the left:

20x-2(4x-5)-(4+6(2x+1))=0

We multiply parentheses

20x-8x-(4+6(2x+1))+10=0



We calculate terms in parentheses: -(4+6(2x+1)), so:

4+6(2x+1)

determiningTheFunctionDomain
6(2x+1)+4

We multiply parentheses

12x+6+4

We add all the numbers together, and all the variables

12x+10

Back to the equation:

-(12x+10)



We add all the numbers together, and all the variables

12x-(12x+10)+10=0

We get rid of parentheses

12x-12x-10+10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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