20x-2(x-5)=3(2x+19)-

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Solution for 20x-2(x-5)=3(2x+19)- equation:



20x-2(x-5)=3(2x+19)-
We move all terms to the left:
20x-2(x-5)-(3(2x+19)-)=0
We multiply parentheses
20x-2x-(3(2x+19)-)+10=0
We calculate terms in parentheses: -(3(2x+19)-), so:
3(2x+19)-
We add all the numbers together, and all the variables
3(2x+19)
We multiply parentheses
6x+57
Back to the equation:
-(6x+57)
We add all the numbers together, and all the variables
18x-(6x+57)+10=0
We get rid of parentheses
18x-6x-57+10=0
We add all the numbers together, and all the variables
12x-47=0
We move all terms containing x to the left, all other terms to the right
12x=47
x=47/12
x=3+11/12

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