20x-2(x-5)=3(2x+19)-

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Solution for 20x-2(x-5)=3(2x+19)- equation: 



20x-2(x-5)=3(2x+19)-

We move all terms to the left:

20x-2(x-5)-(3(2x+19)-)=0

We multiply parentheses

20x-2x-(3(2x+19)-)+10=0



We calculate terms in parentheses: -(3(2x+19)-), so:

3(2x+19)-

We add all the numbers together, and all the variables

3(2x+19)

We multiply parentheses

6x+57

Back to the equation:

-(6x+57)



We add all the numbers together, and all the variables

18x-(6x+57)+10=0

We get rid of parentheses

18x-6x-57+10=0

We add all the numbers together, and all the variables

12x-47=0

We move all terms containing x to the left, all other terms to the right

12x=47

x=47/12

x=3+11/12

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