20x-2=3(5x-2)+5x+4

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Solution for 20x-2=3(5x-2)+5x+4 equation: 



20x-2=3(5x-2)+5x+4

We move all terms to the left:

20x-2-(3(5x-2)+5x+4)=0



We calculate terms in parentheses: -(3(5x-2)+5x+4), so:

3(5x-2)+5x+4

We add all the numbers together, and all the variables

5x+3(5x-2)+4

We multiply parentheses

5x+15x-6+4

We add all the numbers together, and all the variables

20x-2

Back to the equation:

-(20x-2)



We get rid of parentheses

20x-20x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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