20x-2x*x=2x*x/2

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Solution for 20x-2x*x=2x*x/2 equation:



20x-2x*x=2x*x/2
We move all terms to the left:
20x-2x*x-(2x*x/2)=0
We add all the numbers together, and all the variables
20x-2x*x-(+2x*x/2)=0
Wy multiply elements
-2x^2+20x-(+2x*x/2)=0
We get rid of parentheses
-2x^2+20x-2x*x/2=0
We multiply all the terms by the denominator
-2x^2*2+20x*2-2x*x=0
Wy multiply elements
-4x^2-2x^2+40x=0
We add all the numbers together, and all the variables
-6x^2+40x=0
a = -6; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·(-6)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*-6}=\frac{-80}{-12} =6+2/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*-6}=\frac{0}{-12} =0 $

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