20x-3(x-2)=27-6x+2(2x-11)

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Solution for 20x-3(x-2)=27-6x+2(2x-11) equation: 



20x-3(x-2)=27-6x+2(2x-11)

We move all terms to the left:

20x-3(x-2)-(27-6x+2(2x-11))=0

We multiply parentheses

20x-3x-(27-6x+2(2x-11))+6=0



We calculate terms in parentheses: -(27-6x+2(2x-11)), so:

27-6x+2(2x-11)

determiningTheFunctionDomain
-6x+2(2x-11)+27

We multiply parentheses

-6x+4x-22+27

We add all the numbers together, and all the variables

-2x+5

Back to the equation:

-(-2x+5)



We add all the numbers together, and all the variables

17x-(-2x+5)+6=0

We get rid of parentheses

17x+2x-5+6=0

We add all the numbers together, and all the variables

19x+1=0

We move all terms containing x to the left, all other terms to the right

19x=-1

x=-1/19

x=-1/19

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