20x-4/x-4-(2)=20/x+4

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Solution for 20x-4/x-4-(2)=20/x+4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

20*x-(4/x)-4-2 = 20/x+4 // - 20/x+4

20*x-(4/x)-(20/x)-4-4-2 = 0

20*x-4*x^-1-20*x^-1-4-4-2 = 0

20*x^1-24*x^-1-10*x^0 = 0

(20*x^2-10*x^1-24*x^0)/(x^1) = 0 // * x^2

x^1*(20*x^2-10*x^1-24*x^0) = 0

x^1

20*x^2-10*x-24 = 0

20*x^2-10*x-24 = 0

DELTA = (-10)^2-(-24*4*20)

DELTA = 2020

DELTA > 0

x = (2020^(1/2)+10)/(2*20) or x = (10-2020^(1/2))/(2*20)

x = (2*505^(1/2)+10)/40 or x = (10-2*505^(1/2))/40

x in { (10-2*505^(1/2))/40, (2*505^(1/2)+10)/40} 

x in { (10-2*505^(1/2))/40, (2*505^(1/2)+10)/40 }

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