20x-4=2(5x+31)

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Solution for 20x-4=2(5x+31) equation: 



20x-4=2(5x+31)

We move all terms to the left:

20x-4-(2(5x+31))=0



We calculate terms in parentheses: -(2(5x+31)), so:

2(5x+31)

We multiply parentheses

10x+62

Back to the equation:

-(10x+62)



We get rid of parentheses

20x-10x-62-4=0

We add all the numbers together, and all the variables

10x-66=0

We move all terms containing x to the left, all other terms to the right

10x=66

x=66/10

x=6+3/5

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