20x-8-11x=3(3x-4)+4

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Solution for 20x-8-11x=3(3x-4)+4 equation:



20x-8-11x=3(3x-4)+4
We move all terms to the left:
20x-8-11x-(3(3x-4)+4)=0
We add all the numbers together, and all the variables
9x-(3(3x-4)+4)-8=0
We calculate terms in parentheses: -(3(3x-4)+4), so:
3(3x-4)+4
We multiply parentheses
9x-12+4
We add all the numbers together, and all the variables
9x-8
Back to the equation:
-(9x-8)
We get rid of parentheses
9x-9x+8-8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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