20x-8=5(4x+4)x=

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Solution for 20x-8=5(4x+4)x= equation:



20x-8=5(4x+4)x=
We move all terms to the left:
20x-8-(5(4x+4)x)=0
We calculate terms in parentheses: -(5(4x+4)x), so:
5(4x+4)x
We multiply parentheses
20x^2+20x
Back to the equation:
-(20x^2+20x)
We get rid of parentheses
-20x^2+20x-20x-8=0
We add all the numbers together, and all the variables
-20x^2-8=0
a = -20; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·(-20)·(-8)
Δ = -640
Delta is less than zero, so there is no solution for the equation

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